Base | Representation |
---|---|
bin | 10010111110110100011… |
… | …011010000001001101101 |
3 | 11121200220000202000021211 |
4 | 102332310123100021231 |
5 | 132332403421233423 |
6 | 2435122320354421 |
7 | 163145205124225 |
oct | 22766433201155 |
9 | 4550800660254 |
10 | 1304402133613 |
11 | 463214aa9347 |
12 | 190975775a11 |
13 | 9600a126627 |
14 | 471c209b085 |
15 | 23de563110d |
hex | 12fb46d026d |
1304402133613 has 2 divisors, whose sum is σ = 1304402133614. Its totient is φ = 1304402133612.
The previous prime is 1304402133599. The next prime is 1304402133647. The reversal of 1304402133613 is 3163312044031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 701980892649 + 602421240964 = 837843^2 + 776158^2 .
It is a cyclic number.
It is not a de Polignac number, because 1304402133613 - 25 = 1304402133581 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1304402133113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652201066806 + 652201066807.
It is an arithmetic number, because the mean of its divisors is an integer number (652201066807).
Almost surely, 21304402133613 is an apocalyptic number.
It is an amenable number.
1304402133613 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304402133613 is an equidigital number, since it uses as much as digits as its factorization.
1304402133613 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 1304402133613 its reverse (3163312044031), we get a palindrome (4467714177644).
The spelling of 1304402133613 in words is "one trillion, three hundred four billion, four hundred two million, one hundred thirty-three thousand, six hundred thirteen".
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