Base | Representation |
---|---|
bin | 10010111110110100011… |
… | …100010011101010000101 |
3 | 11121200220001021001120201 |
4 | 102332310130103222011 |
5 | 132332404004110432 |
6 | 2435122330330501 |
7 | 163145210355322 |
oct | 22766434235205 |
9 | 4550801231521 |
10 | 1304402410117 |
11 | 463215178064 |
12 | 190975889a31 |
13 | 9600a1c2441 |
14 | 471c212db49 |
15 | 23de5687ee7 |
hex | 12fb4713a85 |
1304402410117 has 2 divisors, whose sum is σ = 1304402410118. Its totient is φ = 1304402410116.
The previous prime is 1304402410111. The next prime is 1304402410147. The reversal of 1304402410117 is 7110142044031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1052083055521 + 252319354596 = 1025711^2 + 502314^2 .
It is a cyclic number.
It is not a de Polignac number, because 1304402410117 - 23 = 1304402410109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1304402410111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652201205058 + 652201205059.
It is an arithmetic number, because the mean of its divisors is an integer number (652201205059).
Almost surely, 21304402410117 is an apocalyptic number.
It is an amenable number.
1304402410117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304402410117 is an equidigital number, since it uses as much as digits as its factorization.
1304402410117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2688, while the sum is 28.
Adding to 1304402410117 its reverse (7110142044031), we get a palindrome (8414544454148).
The spelling of 1304402410117 in words is "one trillion, three hundred four billion, four hundred two million, four hundred ten thousand, one hundred seventeen".
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