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130440241023853 is a prime number
BaseRepresentation
bin11101101010001001111100…
…001110110000101101101101
3122002211222001200011110211111
4131222021330032300231231
5114044113103200230403
61141231230334552021
736321665525521645
oct3552117416605555
9562758050143744
10130440241023853
1138620439540432
1212768238968611
1357a2600b94937
14242d4ac94d525
1510130b3bd856d
hex76a27c3b0b6d

130440241023853 has 2 divisors, whose sum is σ = 130440241023854. Its totient is φ = 130440241023852.

The previous prime is 130440241023817. The next prime is 130440241023877. The reversal of 130440241023853 is 358320142044031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127254937017289 + 3185304006564 = 11280733^2 + 1784742^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130440241023853 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130440241023893) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220120511926 + 65220120511927.

It is an arithmetic number, because the mean of its divisors is an integer number (65220120511927).

Almost surely, 2130440241023853 is an apocalyptic number.

It is an amenable number.

130440241023853 is a deficient number, since it is larger than the sum of its proper divisors (1).

130440241023853 is an equidigital number, since it uses as much as digits as its factorization.

130440241023853 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 276480, while the sum is 40.

Adding to 130440241023853 its reverse (358320142044031), we get a palindrome (488760383067884).

The spelling of 130440241023853 in words is "one hundred thirty trillion, four hundred forty billion, two hundred forty-one million, twenty-three thousand, eight hundred fifty-three".