1304405017 has 2 divisors, whose sum is σ = 1304405018. Its totient is φ = 1304405016.

The previous prime is 1304404999. The next prime is 1304405021. The reversal of 1304405017 is 7105044031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 744798681 + 559606336 = 27291^2 + 23656^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1304405017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1304404982 and 1304405000.

It is not a weakly prime, because it can be changed into another prime (1304405027) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652202508 + 652202509.

It is an arithmetic number, because the mean of its divisors is an integer number (652202509).

Almost surely, 2^1304405017 is an apocalyptic number.

It is an amenable number.

1304405017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304405017 is an equidigital number, since it uses as much as digits as its factorization.

1304405017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1680, while the sum is 25.

The square root of 1304405017 is about 36116.5476893902. The cubic root of 1304405017 is about 1092.6242123571.

Adding to 1304405017 its reverse (7105044031), we get a palindrome (8409449048).

The spelling of 1304405017 in words is "one billion, three hundred four million, four hundred five thousand, seventeen".