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13044124124243 is a prime number
BaseRepresentation
bin1011110111010001001001…
…1000101000010001010011
31201012000011102211021200022
42331310102120220101103
53202203331233433433
643424215441414055
72514256361435132
oct275642230502123
951160142737608
1013044124124243
114179a89010383
12156805693a32b
1373809529b584
143314a6217919
15179493261698
hexbdd12628453

13044124124243 has 2 divisors, whose sum is σ = 13044124124244. Its totient is φ = 13044124124242.

The previous prime is 13044124124237. The next prime is 13044124124249. The reversal of 13044124124243 is 34242142144031.

It is a balanced prime because it is at equal distance from previous prime (13044124124237) and next prime (13044124124249).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13044124124243 is a prime.

It is not a weakly prime, because it can be changed into another prime (13044124124249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522062062121 + 6522062062122.

It is an arithmetic number, because the mean of its divisors is an integer number (6522062062122).

Almost surely, 213044124124243 is an apocalyptic number.

13044124124243 is a deficient number, since it is larger than the sum of its proper divisors (1).

13044124124243 is an equidigital number, since it uses as much as digits as its factorization.

13044124124243 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 73728, while the sum is 35.

Adding to 13044124124243 its reverse (34242142144031), we get a palindrome (47286266268274).

The spelling of 13044124124243 in words is "thirteen trillion, forty-four billion, one hundred twenty-four million, one hundred twenty-four thousand, two hundred forty-three".