Base | Representation |
---|---|
bin | 1011110111010001001001… |
… | …1000101000010001010011 |
3 | 1201012000011102211021200022 |
4 | 2331310102120220101103 |
5 | 3202203331233433433 |
6 | 43424215441414055 |
7 | 2514256361435132 |
oct | 275642230502123 |
9 | 51160142737608 |
10 | 13044124124243 |
11 | 4179a89010383 |
12 | 156805693a32b |
13 | 73809529b584 |
14 | 3314a6217919 |
15 | 179493261698 |
hex | bdd12628453 |
13044124124243 has 2 divisors, whose sum is σ = 13044124124244. Its totient is φ = 13044124124242.
The previous prime is 13044124124237. The next prime is 13044124124249. The reversal of 13044124124243 is 34242142144031.
It is a balanced prime because it is at equal distance from previous prime (13044124124237) and next prime (13044124124249).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13044124124243 is a prime.
It is not a weakly prime, because it can be changed into another prime (13044124124249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522062062121 + 6522062062122.
It is an arithmetic number, because the mean of its divisors is an integer number (6522062062122).
Almost surely, 213044124124243 is an apocalyptic number.
13044124124243 is a deficient number, since it is larger than the sum of its proper divisors (1).
13044124124243 is an equidigital number, since it uses as much as digits as its factorization.
13044124124243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 73728, while the sum is 35.
Adding to 13044124124243 its reverse (34242142144031), we get a palindrome (47286266268274).
The spelling of 13044124124243 in words is "thirteen trillion, forty-four billion, one hundred twenty-four million, one hundred twenty-four thousand, two hundred forty-three".
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