130441310210041 has 2 divisors, whose sum is σ = 130441310210042. Its totient is φ = 130441310210040.

The previous prime is 130441310210027. The next prime is 130441310210047. The reversal of 130441310210041 is 140012013144031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129800357856016 + 640952354025 = 11392996^2 + 800595^2 .

It is a cyclic number.

It is not a de Polignac number, because 130441310210041 - 2¹⁷ = 130441310078969 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130441310209988 and 130441310210015.

It is not a weakly prime, because it can be changed into another prime (130441310210047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220655105020 + 65220655105021.

It is an arithmetic number, because the mean of its divisors is an integer number (65220655105021).

Almost surely, 2^{130441310210041} is an apocalyptic number.

It is an amenable number.

130441310210041 is a deficient number, since it is larger than the sum of its proper divisors (1).

130441310210041 is an equidigital number, since it uses as much as digits as its factorization.

130441310210041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 130441310210041 its reverse (140012013144031), we get a palindrome (270453323354072).

The spelling of 130441310210041 in words is "one hundred thirty trillion, four hundred forty-one billion, three hundred ten million, two hundred ten thousand, forty-one".