Base | Representation |
---|---|
bin | 111100101111011101… |
… | …0001111010111000111 |
3 | 110110200200101212101202 |
4 | 1321132322033113013 |
5 | 4114120441010310 |
6 | 135531322413115 |
7 | 12265313063612 |
oct | 1713672172707 |
9 | 413620355352 |
10 | 130441344455 |
11 | 50357813814 |
12 | 2134466119b |
13 | c3ba4608b6 |
14 | 6455d53179 |
15 | 35d69923a5 |
hex | 1e5ee8f5c7 |
130441344455 has 32 divisors (see below), whose sum is σ = 169984051200. Its totient is φ = 95851728000.
The previous prime is 130441344443. The next prime is 130441344529. The reversal of 130441344455 is 554443144031.
It is a de Polignac number, because none of the positive numbers 2k-130441344455 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 19280 + ... + 511130.
It is an arithmetic number, because the mean of its divisors is an integer number (5312001600).
Almost surely, 2130441344455 is an apocalyptic number.
130441344455 is a deficient number, since it is larger than the sum of its proper divisors (39542706745).
130441344455 is a wasteful number, since it uses less digits than its factorization.
130441344455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 491975.
The product of its (nonzero) digits is 230400, while the sum is 38.
Adding to 130441344455 its reverse (554443144031), we get a palindrome (684884488486).
The spelling of 130441344455 in words is "one hundred thirty billion, four hundred forty-one million, three hundred forty-four thousand, four hundred fifty-five".
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