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130441410204011 is a prime number
BaseRepresentation
bin11101101010001011000001…
…111010110101000101101011
3122002212002002011011222111022
4131222023001322311011223
5114044123002003012021
61141231542342323055
736322036513425314
oct3552130172650553
9562762064158438
10130441410204011
1138620989506825
121276850442948b
1357a2759187c0a
14242d57dd3960b
1510131316871ab
hex76a2c1eb516b

130441410204011 has 2 divisors, whose sum is σ = 130441410204012. Its totient is φ = 130441410204010.

The previous prime is 130441410203987. The next prime is 130441410204023. The reversal of 130441410204011 is 110402014144031.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (110402014144031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130441410204011 is a prime.

It is a super-2 number, since 2×1304414102040112 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130441410204071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220705102005 + 65220705102006.

It is an arithmetic number, because the mean of its divisors is an integer number (65220705102006).

Almost surely, 2130441410204011 is an apocalyptic number.

130441410204011 is a deficient number, since it is larger than the sum of its proper divisors (1).

130441410204011 is an equidigital number, since it uses as much as digits as its factorization.

130441410204011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 26.

Adding to 130441410204011 its reverse (110402014144031), we get a palindrome (240843424348042).

The spelling of 130441410204011 in words is "one hundred thirty trillion, four hundred forty-one billion, four hundred ten million, two hundred four thousand, eleven".