130442013024133 has 2 divisors, whose sum is σ = 130442013024134. Its totient is φ = 130442013024132.

The previous prime is 130442013024109. The next prime is 130442013024149. The reversal of 130442013024133 is 331420310244031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96221934881284 + 34220078142849 = 9809278^2 + 5849793^2 .

It is a cyclic number.

It is not a de Polignac number, because 130442013024133 - 2¹⁷ = 130442012893061 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130442013024095 and 130442013024104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130442013024163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65221006512066 + 65221006512067.

It is an arithmetic number, because the mean of its divisors is an integer number (65221006512067).

Almost surely, 2^{130442013024133} is an apocalyptic number.

It is an amenable number.

130442013024133 is a deficient number, since it is larger than the sum of its proper divisors (1).

130442013024133 is an equidigital number, since it uses as much as digits as its factorization.

130442013024133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 130442013024133 its reverse (331420310244031), we get a palindrome (461862323268164).

The spelling of 130442013024133 in words is "one hundred thirty trillion, four hundred forty-two billion, thirteen million, twenty-four thousand, one hundred thirty-three".