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1304422414342 = 2652211207171
BaseRepresentation
bin10010111110110101101…
…000100111100000000110
311121200221102220101012221
4102332311220213200012
5132332424114224332
62435124323202554
7163145542402555
oct22766550474006
94550842811187
101304422414342
114632254a0583
1219098051645a
13960113a7768
14471c4a59d9c
1523de72da297
hex12fb5a27806

1304422414342 has 4 divisors (see below), whose sum is σ = 1956633621516. Its totient is φ = 652211207170.

The previous prime is 1304422414333. The next prime is 1304422414343. The reversal of 1304422414342 is 2434142244031.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 1304422414298 and 1304422414307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1304422414343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 326105603584 + ... + 326105603587.

It is an arithmetic number, because the mean of its divisors is an integer number (489158405379).

Almost surely, 21304422414342 is an apocalyptic number.

1304422414342 is a deficient number, since it is larger than the sum of its proper divisors (652211207174).

1304422414342 is an equidigital number, since it uses as much as digits as its factorization.

1304422414342 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 652211207173.

The product of its (nonzero) digits is 73728, while the sum is 34.

Adding to 1304422414342 its reverse (2434142244031), we get a palindrome (3738564658373).

The spelling of 1304422414342 in words is "one trillion, three hundred four billion, four hundred twenty-two million, four hundred fourteen thousand, three hundred forty-two".

Divisors: 1 2 652211207171 1304422414342