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13044231100141 = 17775871988963
BaseRepresentation
bin1011110111010001100011…
…0000101101011011101101
31201012000102220010020000121
42331310120300231123231
53202204041130201031
643424234222324541
72514262130633203
oct275643060553355
951160386106017
1013044231100141
11417a033436a0a
121568086729751
137380b14b5317
143314b6503073
1517949c843011
hexbdd18c2d6ed

13044231100141 has 8 divisors (see below), whose sum is σ = 13811570578944. Its totient is φ = 12276895151040.

The previous prime is 13044231100139. The next prime is 13044231100163. The reversal of 13044231100141 is 14100113244031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13044231100141 - 21 = 13044231100139 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13044231100171) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12695326 + ... + 13684288.

It is an arithmetic number, because the mean of its divisors is an integer number (1726446322368).

Almost surely, 213044231100141 is an apocalyptic number.

It is an amenable number.

13044231100141 is a deficient number, since it is larger than the sum of its proper divisors (767339478803).

13044231100141 is an equidigital number, since it uses as much as digits as its factorization.

13044231100141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1764851.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13044231100141 its reverse (14100113244031), we get a palindrome (27144344344172).

The spelling of 13044231100141 in words is "thirteen trillion, forty-four billion, two hundred thirty-one million, one hundred thousand, one hundred forty-one".

Divisors: 1 17 775871 988963 13189807 16812371 767307711773 13044231100141