Base | Representation |
---|---|
bin | 1011110111010001100011… |
… | …0000101101011100000011 |
3 | 1201012000102220010020001102 |
4 | 2331310120300231130003 |
5 | 3202204041130201123 |
6 | 43424234222325015 |
7 | 2514262130633234 |
oct | 275643060553403 |
9 | 51160386106042 |
10 | 13044231100163 |
11 | 417a033436a2a |
12 | 156808672976b |
13 | 7380b14b5333 |
14 | 3314b650308b |
15 | 17949c843028 |
hex | bdd18c2d703 |
13044231100163 has 2 divisors, whose sum is σ = 13044231100164. Its totient is φ = 13044231100162.
The previous prime is 13044231100139. The next prime is 13044231100171. The reversal of 13044231100163 is 36100113244031.
It is a happy number.
13044231100163 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13044231100163 - 230 = 13043157358339 is a prime.
It is not a weakly prime, because it can be changed into another prime (13044231600163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522115550081 + 6522115550082.
It is an arithmetic number, because the mean of its divisors is an integer number (6522115550082).
Almost surely, 213044231100163 is an apocalyptic number.
13044231100163 is a deficient number, since it is larger than the sum of its proper divisors (1).
13044231100163 is an equidigital number, since it uses as much as digits as its factorization.
13044231100163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 13044231100163 its reverse (36100113244031), we get a palindrome (49144344344194).
The spelling of 13044231100163 in words is "thirteen trillion, forty-four billion, two hundred thirty-one million, one hundred thousand, one hundred sixty-three".
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