Search a number
-
+
13044241320042 = 233735828526059
BaseRepresentation
bin1011110111010001100101…
…0111101100100001101010
31201012000110121100110002110
42331310121113230201222
53202204101234220132
643424235225343150
72514262313536632
oct275643127544152
951160417313073
1013044241320042
11417a039187309
12156808a037ab6
137380b3652cba
143314b7a036c2
1517949d6b11cc
hexbdd195ec86a

13044241320042 has 16 divisors (see below), whose sum is σ = 26158424957280. Its totient is φ = 4336423387152.

The previous prime is 13044241320037. The next prime is 13044241320067. The reversal of 13044241320042 is 24002314244031.

It is a junction number, because it is equal to n+sod(n) for n = 13044241319991 and 13044241320009.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2914260792 + ... + 2914265267.

It is an arithmetic number, because the mean of its divisors is an integer number (1634901559830).

Almost surely, 213044241320042 is an apocalyptic number.

13044241320042 is an abundant number, since it is smaller than the sum of its proper divisors (13114183637238).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13044241320042 is a wasteful number, since it uses less digits than its factorization.

13044241320042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5828526437.

The product of its (nonzero) digits is 18432, while the sum is 30.

Adding to 13044241320042 its reverse (24002314244031), we get a palindrome (37046555564073).

The spelling of 13044241320042 in words is "thirteen trillion, forty-four billion, two hundred forty-one million, three hundred twenty thousand, forty-two".

Divisors: 1 2 3 6 373 746 1119 2238 5828526059 11657052118 17485578177 34971156354 2174040220007 4348080440014 6522120660021 13044241320042