13044241320043 has 24 divisors (see below), whose sum is σ = 13364932089600. Its totient is φ = 12728396696400.

The previous prime is 13044241320037. The next prime is 13044241320067. The reversal of 13044241320043 is 34002314244031.

It is not a de Polignac number, because 13044241320043 - 2¹³ = 13044241311851 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13044241319987 and 13044241320014.

It is not an unprimeable number, because it can be changed into a prime (13044241320083) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 515427396 + ... + 515452702.

It is an arithmetic number, because the mean of its divisors is an integer number (556872170400).

Almost surely, 2^{13044241320043} is an apocalyptic number.

13044241320043 is a deficient number, since it is larger than the sum of its proper divisors (320690769557).

13044241320043 is an equidigital number, since it uses as much as digits as its factorization.

13044241320043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25959 (or 25768 counting only the distinct ones).

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 13044241320043 its reverse (34002314244031), we get a palindrome (47046555564074).

The spelling of 13044241320043 in words is "thirteen trillion, forty-four billion, two hundred forty-one million, three hundred twenty thousand, forty-three".