Base | Representation |
---|---|
bin | 1011110111010001100101… |
… | …0111101111110010110101 |
3 | 1201012000110121101010110021 |
4 | 2331310121113233302311 |
5 | 3202204101240132204 |
6 | 43424235225525141 |
7 | 2514262313623645 |
oct | 275643127576265 |
9 | 51160417333407 |
10 | 13044241333429 |
11 | 417a039196379 |
12 | 156808a0437b1 |
13 | 7380b3659117 |
14 | 3314b7a08525 |
15 | 17949d6b5154 |
hex | bdd195efcb5 |
13044241333429 has 2 divisors, whose sum is σ = 13044241333430. Its totient is φ = 13044241333428.
The previous prime is 13044241333379. The next prime is 13044241333441. The reversal of 13044241333429 is 92433314244031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10301981508900 + 2742259824529 = 3209670^2 + 1655977^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13044241333429 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13044241333229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522120666714 + 6522120666715.
It is an arithmetic number, because the mean of its divisors is an integer number (6522120666715).
Almost surely, 213044241333429 is an apocalyptic number.
It is an amenable number.
13044241333429 is a deficient number, since it is larger than the sum of its proper divisors (1).
13044241333429 is an equidigital number, since it uses as much as digits as its factorization.
13044241333429 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 746496, while the sum is 43.
The spelling of 13044241333429 in words is "thirteen trillion, forty-four billion, two hundred forty-one million, three hundred thirty-three thousand, four hundred twenty-nine".
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