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130442414010217 is a prime number
BaseRepresentation
bin11101101010001011111101…
…110000000010111101101001
3122002212011200010000121201221
4131222023331300002331221
5114044132030441311332
61141232230121342041
736322103422561111
oct3552137560027551
9562764603017657
10130442414010217
113862135409a231
1212768744637921
1357a288912869a
14242d637398041
15101318e86b297
hex76a2fdc02f69

130442414010217 has 2 divisors, whose sum is σ = 130442414010218. Its totient is φ = 130442414010216.

The previous prime is 130442414010191. The next prime is 130442414010257. The reversal of 130442414010217 is 712010414244031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109484183513961 + 20958230496256 = 10463469^2 + 4578016^2 .

It is a cyclic number.

It is not a de Polignac number, because 130442414010217 - 219 = 130442413485929 is a prime.

It is not a weakly prime, because it can be changed into another prime (130442414010257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65221207005108 + 65221207005109.

It is an arithmetic number, because the mean of its divisors is an integer number (65221207005109).

Almost surely, 2130442414010217 is an apocalyptic number.

It is an amenable number.

130442414010217 is a deficient number, since it is larger than the sum of its proper divisors (1).

130442414010217 is an equidigital number, since it uses as much as digits as its factorization.

130442414010217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21504, while the sum is 34.

Adding to 130442414010217 its reverse (712010414244031), we get a palindrome (842452828254248).

The spelling of 130442414010217 in words is "one hundred thirty trillion, four hundred forty-two billion, four hundred fourteen million, ten thousand, two hundred seventeen".