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1304430141103 = 2356714353961
BaseRepresentation
bin10010111110110110000…
…110000101111010101111
311121200221222102221100021
4102332312012011322233
5132332433104003403
62435125200543011
7163145665153555
oct22766606057257
94550858387307
101304430141103
11463229898831
12190983021a67
1396012b816cb
14471c5aabbd5
1523de7d148bd
hex12fb6185eaf

1304430141103 has 4 divisors (see below), whose sum is σ = 1361144495088. Its totient is φ = 1247715787120.

The previous prime is 1304430141101. The next prime is 1304430141191. The reversal of 1304430141103 is 3011410344031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1304430141103 - 21 = 1304430141101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1304430141101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28357176958 + ... + 28357177003.

It is an arithmetic number, because the mean of its divisors is an integer number (340286123772).

Almost surely, 21304430141103 is an apocalyptic number.

1304430141103 is a deficient number, since it is larger than the sum of its proper divisors (56714353985).

1304430141103 is an equidigital number, since it uses as much as digits as its factorization.

1304430141103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56714353984.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1304430141103 its reverse (3011410344031), we get a palindrome (4315840485134).

The spelling of 1304430141103 in words is "one trillion, three hundred four billion, four hundred thirty million, one hundred forty-one thousand, one hundred three".

Divisors: 1 23 56714353961 1304430141103