Base | Representation |
---|---|
bin | 1011110111010001110100… |
… | …0100101000010101100011 |
3 | 1201012000121221020000022201 |
4 | 2331310131010220111203 |
5 | 3202204213134243021 |
6 | 43424245324514031 |
7 | 2514263666505316 |
oct | 275643504502543 |
9 | 51160557200281 |
10 | 13044303431011 |
11 | 417a07024a196 |
12 | 15680a69ab917 |
13 | 7380c348ba58 |
14 | 3314c1d7097d |
15 | 1794a3d7e591 |
hex | bdd1d128563 |
13044303431011 has 2 divisors, whose sum is σ = 13044303431012. Its totient is φ = 13044303431010.
The previous prime is 13044303430957. The next prime is 13044303431053. The reversal of 13044303431011 is 11013430344031.
13044303431011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13044303431011 - 213 = 13044303422819 is a prime.
It is not a weakly prime, because it can be changed into another prime (13044303431311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522151715505 + 6522151715506.
It is an arithmetic number, because the mean of its divisors is an integer number (6522151715506).
Almost surely, 213044303431011 is an apocalyptic number.
13044303431011 is a deficient number, since it is larger than the sum of its proper divisors (1).
13044303431011 is an equidigital number, since it uses as much as digits as its factorization.
13044303431011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 13044303431011 its reverse (11013430344031), we get a palindrome (24057733775042).
The spelling of 13044303431011 in words is "thirteen trillion, forty-four billion, three hundred three million, four hundred thirty-one thousand, eleven".
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