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13044303431053 is a prime number
BaseRepresentation
bin1011110111010001110100…
…0100101000010110001101
31201012000121221020000101021
42331310131010220112031
53202204213134243203
643424245324514141
72514263666505406
oct275643504502615
951160557200337
1013044303431053
11417a07024a224
1215680a69ab951
137380c348ba8b
143314c1d709ad
151794a3d7e5bd
hexbdd1d12858d

13044303431053 has 2 divisors, whose sum is σ = 13044303431054. Its totient is φ = 13044303431052.

The previous prime is 13044303431011. The next prime is 13044303431063. The reversal of 13044303431053 is 35013430344031.

13044303431053 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11663577379204 + 1380726051849 = 3415198^2 + 1175043^2 .

It is a cyclic number.

It is not a de Polignac number, because 13044303431053 - 29 = 13044303430541 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13044303431063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522151715526 + 6522151715527.

It is an arithmetic number, because the mean of its divisors is an integer number (6522151715527).

Almost surely, 213044303431053 is an apocalyptic number.

It is an amenable number.

13044303431053 is a deficient number, since it is larger than the sum of its proper divisors (1).

13044303431053 is an equidigital number, since it uses as much as digits as its factorization.

13044303431053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 77760, while the sum is 34.

Adding to 13044303431053 its reverse (35013430344031), we get a palindrome (48057733775084).

The spelling of 13044303431053 in words is "thirteen trillion, forty-four billion, three hundred three million, four hundred thirty-one thousand, fifty-three".