Base | Representation |
---|---|
bin | 1011110111010001110100… |
… | …0100101011000011010010 |
3 | 1201012000121221020120120112 |
4 | 2331310131010223003102 |
5 | 3202204213140122010 |
6 | 43424245325041322 |
7 | 2514263666552612 |
oct | 275643504530322 |
9 | 51160557216515 |
10 | 13044303442130 |
11 | 417a070257584 |
12 | 15680a69b6242 |
13 | 7380c3493b2c |
14 | 3314c1d74a42 |
15 | 1794a3d82a05 |
hex | bdd1d12b0d2 |
13044303442130 has 32 divisors (see below), whose sum is σ = 24303999283200. Its totient is φ = 5034770419392.
The previous prime is 13044303442127. The next prime is 13044303442139. The reversal of 13044303442130 is 3124430344031.
13044303442130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not an unprimeable number, because it can be changed into a prime (13044303442139) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13041590 + ... + 14006129.
It is an arithmetic number, because the mean of its divisors is an integer number (759499977600).
Almost surely, 213044303442130 is an apocalyptic number.
13044303442130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13044303442130 is a deficient number, since it is larger than the sum of its proper divisors (11259695841070).
13044303442130 is a wasteful number, since it uses less digits than its factorization.
13044303442130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27049418.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 13044303442130 its reverse (3124430344031), we get a palindrome (16168733786161).
The spelling of 13044303442130 in words is "thirteen trillion, forty-four billion, three hundred three million, four hundred forty-two thousand, one hundred thirty".
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