Base | Representation |
---|---|
bin | 1011110111010001110110… |
… | …1001101000110100010011 |
3 | 1201012000122121110212222222 |
4 | 2331310131221220310103 |
5 | 3202204223130213212 |
6 | 43424250312451255 |
7 | 2514264145122062 |
oct | 275643551506423 |
9 | 51160577425888 |
10 | 13044313132307 |
11 | 417a075775996 |
12 | 15680aa0a9b2b |
13 | 7380c54a7672 |
14 | 3314c33781d9 |
15 | 1794a4b48c72 |
hex | bdd1da68d13 |
13044313132307 has 2 divisors, whose sum is σ = 13044313132308. Its totient is φ = 13044313132306.
The previous prime is 13044313132289. The next prime is 13044313132387. The reversal of 13044313132307 is 70323131344031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13044313132307 - 26 = 13044313132243 is a prime.
It is not a weakly prime, because it can be changed into another prime (13044313132387) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522156566153 + 6522156566154.
It is an arithmetic number, because the mean of its divisors is an integer number (6522156566154).
Almost surely, 213044313132307 is an apocalyptic number.
13044313132307 is a deficient number, since it is larger than the sum of its proper divisors (1).
13044313132307 is an equidigital number, since it uses as much as digits as its factorization.
13044313132307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54432, while the sum is 35.
Adding to 13044313132307 its reverse (70323131344031), we get a palindrome (83367444476338).
The spelling of 13044313132307 in words is "thirteen trillion, forty-four billion, three hundred thirteen million, one hundred thirty-two thousand, three hundred seven".
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