Base | Representation |
---|---|
bin | 11101101010001100101001… |
… | …001010101001010100000110 |
3 | 122002212020112212121211020210 |
4 | 131222030221022221110012 |
5 | 114044140023423401314 |
6 | 1141232430301340250 |
7 | 36322130446036155 |
oct | 3552145112512406 |
9 | 562766485554223 |
10 | 130443142403334 |
11 | 38621698271812 |
12 | 12768908567686 |
13 | 57a2973cc9527 |
14 | 242d6a600359c |
15 | 10131d379b559 |
hex | 76a3292a9506 |
130443142403334 has 32 divisors (see below), whose sum is σ = 274056208185600. Its totient is φ = 41311435813472.
The previous prime is 130443142403309. The next prime is 130443142403417. The reversal of 130443142403334 is 433304241344031.
It is a junction number, because it is equal to n+sod(n) for n = 130443142403292 and 130443142403301.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3171926292 + ... + 3171967415.
It is an arithmetic number, because the mean of its divisors is an integer number (8564256505800).
Almost surely, 2130443142403334 is an apocalyptic number.
130443142403334 is an abundant number, since it is smaller than the sum of its proper divisors (143613065782266).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130443142403334 is a wasteful number, since it uses less digits than its factorization.
130443142403334 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6343893884.
The product of its (nonzero) digits is 497664, while the sum is 39.
Adding to 130443142403334 its reverse (433304241344031), we get a palindrome (563747383747365).
The spelling of 130443142403334 in words is "one hundred thirty trillion, four hundred forty-three billion, one hundred forty-two million, four hundred three thousand, three hundred thirty-four".
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