130443517 has 2 divisors, whose sum is σ = 130443518. Its totient is φ = 130443516.

The previous prime is 130443487. The next prime is 130443527. The reversal of 130443517 is 715344031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108597241 + 21846276 = 10421^2 + 4674^2 .

It is an emirp because it is prime and its reverse (715344031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130443517 - 2¹¹ = 130441469 is a prime.

It is a super-2 number, since 2×130443517² = 34031022254658578, which contains 22 as substring.

It is a Chen prime.

It is equal to p_7401853 and since 130443517 and 7401853 have the same sum of digits, it is a Honaker prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130443527) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65221758 + 65221759.

It is an arithmetic number, because the mean of its divisors is an integer number (65221759).

Almost surely, 2^130443517 is an apocalyptic number.

It is an amenable number.

130443517 is a deficient number, since it is larger than the sum of its proper divisors (1).

130443517 is an equidigital number, since it uses as much as digits as its factorization.

130443517 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5040, while the sum is 28.

The square root of 130443517 is about 11421.1871974852. The cubic root of 130443517 is about 507.1551421288.

Adding to 130443517 its reverse (715344031), we get a palindrome (845787548).

It can be divided in two parts, 13044 and 3517, that added together give a palindrome (16561).

The spelling of 130443517 in words is "one hundred thirty million, four hundred forty-three thousand, five hundred seventeen".