Base | Representation |
---|---|
bin | 11101101010001101101001… |
… | …011010100010101010011110 |
3 | 122002212100022222220021021012 |
4 | 131222031221122202222132 |
5 | 114044144230344442342 |
6 | 1141233125244535222 |
7 | 36322166245103525 |
oct | 3552155132425236 |
9 | 562770288807235 |
10 | 130444220312222 |
11 | 386220a0768703 |
12 | 12768b69551512 |
13 | 57a2ab641403b |
14 | 242d7692314bc |
15 | 101324821bb82 |
hex | 76a3696a2a9e |
130444220312222 has 4 divisors (see below), whose sum is σ = 195666330468336. Its totient is φ = 65222110156110.
The previous prime is 130444220312221. The next prime is 130444220312251. The reversal of 130444220312222 is 222213022444031.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×1304442203122222 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130444220312221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32611055078054 + ... + 32611055078057.
It is an arithmetic number, because the mean of its divisors is an integer number (48916582617084).
Almost surely, 2130444220312222 is an apocalyptic number.
130444220312222 is a deficient number, since it is larger than the sum of its proper divisors (65222110156114).
130444220312222 is an equidigital number, since it uses as much as digits as its factorization.
130444220312222 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65222110156113.
The product of its (nonzero) digits is 36864, while the sum is 32.
Adding to 130444220312222 its reverse (222213022444031), we get a palindrome (352657242756253).
The spelling of 130444220312222 in words is "one hundred thirty trillion, four hundred forty-four billion, two hundred twenty million, three hundred twelve thousand, two hundred twenty-two".
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