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130444220312222 = 265222110156111
BaseRepresentation
bin11101101010001101101001…
…011010100010101010011110
3122002212100022222220021021012
4131222031221122202222132
5114044144230344442342
61141233125244535222
736322166245103525
oct3552155132425236
9562770288807235
10130444220312222
11386220a0768703
1212768b69551512
1357a2ab641403b
14242d7692314bc
15101324821bb82
hex76a3696a2a9e

130444220312222 has 4 divisors (see below), whose sum is σ = 195666330468336. Its totient is φ = 65222110156110.

The previous prime is 130444220312221. The next prime is 130444220312251. The reversal of 130444220312222 is 222213022444031.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×1304442203122222 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130444220312221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32611055078054 + ... + 32611055078057.

It is an arithmetic number, because the mean of its divisors is an integer number (48916582617084).

Almost surely, 2130444220312222 is an apocalyptic number.

130444220312222 is a deficient number, since it is larger than the sum of its proper divisors (65222110156114).

130444220312222 is an equidigital number, since it uses as much as digits as its factorization.

130444220312222 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65222110156113.

The product of its (nonzero) digits is 36864, while the sum is 32.

Adding to 130444220312222 its reverse (222213022444031), we get a palindrome (352657242756253).

The spelling of 130444220312222 in words is "one hundred thirty trillion, four hundred forty-four billion, two hundred twenty million, three hundred twelve thousand, two hundred twenty-two".

Divisors: 1 2 65222110156111 130444220312222