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1304442322013 is a prime number
BaseRepresentation
bin10010111110110110110…
…100100011110001011101
311121200222211100210102002
4102332312310203301131
5132332444213301023
62435130314012045
7163146203535455
oct22766664436135
94550884323362
101304442322013
114632357584a6
12190987117025
1396015557b4c
14471c755cd65
1523de8e1db28
hex12fb6d23c5d

1304442322013 has 2 divisors, whose sum is σ = 1304442322014. Its totient is φ = 1304442322012.

The previous prime is 1304442321991. The next prime is 1304442322039. The reversal of 1304442322013 is 3102232444031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1278396558244 + 26045763769 = 1130662^2 + 161387^2 .

It is a cyclic number.

It is not a de Polignac number, because 1304442322013 - 212 = 1304442317917 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1304442322613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652221161006 + 652221161007.

It is an arithmetic number, because the mean of its divisors is an integer number (652221161007).

Almost surely, 21304442322013 is an apocalyptic number.

It is an amenable number.

1304442322013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304442322013 is an equidigital number, since it uses as much as digits as its factorization.

1304442322013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 1304442322013 its reverse (3102232444031), we get a palindrome (4406674766044).

The spelling of 1304442322013 in words is "one trillion, three hundred four billion, four hundred forty-two million, three hundred twenty-two thousand, thirteen".