Base | Representation |
---|---|
bin | 10010111110110110110… |
… | …100100011110001011101 |
3 | 11121200222211100210102002 |
4 | 102332312310203301131 |
5 | 132332444213301023 |
6 | 2435130314012045 |
7 | 163146203535455 |
oct | 22766664436135 |
9 | 4550884323362 |
10 | 1304442322013 |
11 | 4632357584a6 |
12 | 190987117025 |
13 | 96015557b4c |
14 | 471c755cd65 |
15 | 23de8e1db28 |
hex | 12fb6d23c5d |
1304442322013 has 2 divisors, whose sum is σ = 1304442322014. Its totient is φ = 1304442322012.
The previous prime is 1304442321991. The next prime is 1304442322039. The reversal of 1304442322013 is 3102232444031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1278396558244 + 26045763769 = 1130662^2 + 161387^2 .
It is a cyclic number.
It is not a de Polignac number, because 1304442322013 - 212 = 1304442317917 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1304442322613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652221161006 + 652221161007.
It is an arithmetic number, because the mean of its divisors is an integer number (652221161007).
Almost surely, 21304442322013 is an apocalyptic number.
It is an amenable number.
1304442322013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304442322013 is an equidigital number, since it uses as much as digits as its factorization.
1304442322013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 1304442322013 its reverse (3102232444031), we get a palindrome (4406674766044).
The spelling of 1304442322013 in words is "one trillion, three hundred four billion, four hundred forty-two million, three hundred twenty-two thousand, thirteen".
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