Base | Representation |
---|---|
bin | 1011110111010010010011… |
… | …1000011100011110011111 |
3 | 1201012000222001202200122222 |
4 | 2331310210320130132133 |
5 | 3202210000210020211 |
6 | 43424310325055555 |
7 | 2514300150260642 |
oct | 275644470343637 |
9 | 51160861680588 |
10 | 13044434454431 |
11 | 417a128200006 |
12 | 15681228575bb |
13 | 7381146752c3 |
14 | 3314d5519a59 |
15 | 1794b06111db |
hex | bdd24e1c79f |
13044434454431 has 2 divisors, whose sum is σ = 13044434454432. Its totient is φ = 13044434454430.
The previous prime is 13044434454377. The next prime is 13044434454437. The reversal of 13044434454431 is 13445443444031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13044434454431 is a prime.
It is a super-2 number, since 2×130444344544312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13044434454437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522217227215 + 6522217227216.
It is an arithmetic number, because the mean of its divisors is an integer number (6522217227216).
Almost surely, 213044434454431 is an apocalyptic number.
13044434454431 is a deficient number, since it is larger than the sum of its proper divisors (1).
13044434454431 is an equidigital number, since it uses as much as digits as its factorization.
13044434454431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2211840, while the sum is 44.
Adding to 13044434454431 its reverse (13445443444031), we get a palindrome (26489877898462).
The spelling of 13044434454431 in words is "thirteen trillion, forty-four billion, four hundred thirty-four million, four hundred fifty-four thousand, four hundred thirty-one".
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