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13044901733 is a prime number
BaseRepresentation
bin11000010011000100…
…10110011101100101
31020200010021200001122
430021202112131211
5203203443323413
65554233303325
7641156556323
oct141142263545
936603250048
1013044901733
115594563826
122640864b45
1312cb793686
148ba6d6d13
15515371108
hex309896765

13044901733 has 2 divisors, whose sum is σ = 13044901734. Its totient is φ = 13044901732.

The previous prime is 13044901729. The next prime is 13044901823. The reversal of 13044901733 is 33710944031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10527170404 + 2517731329 = 102602^2 + 50177^2 .

It is a cyclic number.

It is not a de Polignac number, because 13044901733 - 22 = 13044901729 is a prime.

It is a super-2 number, since 2×130449017332 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13044901693 and 13044901702.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13044961733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522450866 + 6522450867.

It is an arithmetic number, because the mean of its divisors is an integer number (6522450867).

Almost surely, 213044901733 is an apocalyptic number.

It is an amenable number.

13044901733 is a deficient number, since it is larger than the sum of its proper divisors (1).

13044901733 is an equidigital number, since it uses as much as digits as its factorization.

13044901733 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27216, while the sum is 35.

The spelling of 13044901733 in words is "thirteen billion, forty-four million, nine hundred one thousand, seven hundred thirty-three".