Base | Representation |
---|---|
bin | 10010111110111010111… |
… | …100100000010101001011 |
3 | 11121201011122120002212201 |
4 | 102332322330200111023 |
5 | 132333114421421211 |
6 | 2435141225021031 |
7 | 163151003625253 |
oct | 22767274402513 |
9 | 4551148502781 |
10 | 1304511513931 |
11 | 4632708173aa |
12 | 1909a6324777 |
13 | 960269a2902 |
14 | 471d2810963 |
15 | 23e0003a0c1 |
hex | 12fbaf2054b |
1304511513931 has 2 divisors, whose sum is σ = 1304511513932. Its totient is φ = 1304511513930.
The previous prime is 1304511513913. The next prime is 1304511513941. The reversal of 1304511513931 is 1393151154031.
Together with previous prime (1304511513913) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1304511513931 - 27 = 1304511513803 is a prime.
It is a super-2 number, since 2×13045115139312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1304511513941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652255756965 + 652255756966.
It is an arithmetic number, because the mean of its divisors is an integer number (652255756966).
Almost surely, 21304511513931 is an apocalyptic number.
1304511513931 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304511513931 is an equidigital number, since it uses as much as digits as its factorization.
1304511513931 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24300, while the sum is 37.
Adding to 1304511513931 its reverse (1393151154031), we get a palindrome (2697662667962).
The spelling of 1304511513931 in words is "one trillion, three hundred four billion, five hundred eleven million, five hundred thirteen thousand, nine hundred thirty-one".
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