Base | Representation |
---|---|
bin | 10010111110111010111… |
… | …100100000010101010101 |
3 | 11121201011122120002220002 |
4 | 102332322330200111111 |
5 | 132333114421421231 |
6 | 2435141225021045 |
7 | 163151003625266 |
oct | 22767274402525 |
9 | 4551148502802 |
10 | 1304511513941 |
11 | 463270817409 |
12 | 1909a6324785 |
13 | 960269a290c |
14 | 471d281096d |
15 | 23e0003a0cb |
hex | 12fbaf20555 |
1304511513941 has 2 divisors, whose sum is σ = 1304511513942. Its totient is φ = 1304511513940.
The previous prime is 1304511513931. The next prime is 1304511513961. The reversal of 1304511513941 is 1493151154031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1135352049841 + 169159464100 = 1065529^2 + 411290^2 .
It is a cyclic number.
It is not a de Polignac number, because 1304511513941 - 214 = 1304511497557 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1304511513895 and 1304511513904.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1304511513931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652255756970 + 652255756971.
It is an arithmetic number, because the mean of its divisors is an integer number (652255756971).
Almost surely, 21304511513941 is an apocalyptic number.
It is an amenable number.
1304511513941 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304511513941 is an equidigital number, since it uses as much as digits as its factorization.
1304511513941 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32400, while the sum is 38.
Adding to 1304511513941 its reverse (1493151154031), we get a palindrome (2797662667972).
The spelling of 1304511513941 in words is "one trillion, three hundred four billion, five hundred eleven million, five hundred thirteen thousand, nine hundred forty-one".
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