Base | Representation |
---|---|
bin | 10010111110111010111… |
… | …100100000010110010101 |
3 | 11121201011122120002222110 |
4 | 102332322330200112111 |
5 | 132333114421422010 |
6 | 2435141225021233 |
7 | 163151003625420 |
oct | 22767274402625 |
9 | 4551148502873 |
10 | 1304511514005 |
11 | 463270817467 |
12 | 1909a6324819 |
13 | 960269a295b |
14 | 471d28109b7 |
15 | 23e0003a120 |
hex | 12fbaf20595 |
1304511514005 has 16 divisors (see below), whose sum is σ = 2385392482944. Its totient is φ = 596348120640.
The previous prime is 1304511513979. The next prime is 1304511514057. The reversal of 1304511514005 is 5004151154031.
It is not a de Polignac number, because 1304511514005 - 26 = 1304511513941 is a prime.
It is a super-2 number, since 2×13045115140052 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6211959486 + ... + 6211959695.
It is an arithmetic number, because the mean of its divisors is an integer number (149087030184).
Almost surely, 21304511514005 is an apocalyptic number.
1304511514005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1304511514005 is a deficient number, since it is larger than the sum of its proper divisors (1080880968939).
1304511514005 is a wasteful number, since it uses less digits than its factorization.
1304511514005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12423919196.
The product of its (nonzero) digits is 6000, while the sum is 30.
Adding to 1304511514005 its reverse (5004151154031), we get a palindrome (6308662668036).
The spelling of 1304511514005 in words is "one trillion, three hundred four billion, five hundred eleven million, five hundred fourteen thousand, five".
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