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13045215555133 is a prime number
BaseRepresentation
bin1011110111010101001101…
…1100000110111000111101
31201012002222111112201101121
42331311103130012320331
53202213100140231013
643424520030510541
72514325413441316
oct275652334067075
951162874481347
1013045215555133
11417a499102583
121568300365451
1373820a43ba78
1433156b16560d
15179508ea358d
hexbdd53706e3d

13045215555133 has 2 divisors, whose sum is σ = 13045215555134. Its totient is φ = 13045215555132.

The previous prime is 13045215555083. The next prime is 13045215555137. The reversal of 13045215555133 is 33155551254031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7669504355769 + 5375711199364 = 2769387^2 + 2318558^2 .

It is a cyclic number.

It is not a de Polignac number, because 13045215555133 - 241 = 10846192299581 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13045215555133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13045215555137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522607777566 + 6522607777567.

It is an arithmetic number, because the mean of its divisors is an integer number (6522607777567).

Almost surely, 213045215555133 is an apocalyptic number.

It is an amenable number.

13045215555133 is a deficient number, since it is larger than the sum of its proper divisors (1).

13045215555133 is an equidigital number, since it uses as much as digits as its factorization.

13045215555133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 675000, while the sum is 43.

The spelling of 13045215555133 in words is "thirteen trillion, forty-five billion, two hundred fifteen million, five hundred fifty-five thousand, one hundred thirty-three".