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13045540044011 is a prime number
BaseRepresentation
bin1011110111010110011011…
…0001111011110011101011
31201012010211010010110110012
42331311212301323303223
53202214231222402021
643425012141442135
72514336433524116
oct275654661736353
951163733113405
1013045540044011
11417a645292902
121568390b7034b
1373825c732217
1433159c2b157d
151795276ed35b
hexbdd66c7bceb

13045540044011 has 2 divisors, whose sum is σ = 13045540044012. Its totient is φ = 13045540044010.

The previous prime is 13045540043953. The next prime is 13045540044067. The reversal of 13045540044011 is 11044004554031.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13045540044011 is a prime.

It is a super-2 number, since 2×130455400440112 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13045540047011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522770022005 + 6522770022006.

It is an arithmetic number, because the mean of its divisors is an integer number (6522770022006).

Almost surely, 213045540044011 is an apocalyptic number.

13045540044011 is a deficient number, since it is larger than the sum of its proper divisors (1).

13045540044011 is an equidigital number, since it uses as much as digits as its factorization.

13045540044011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19200, while the sum is 32.

Adding to 13045540044011 its reverse (11044004554031), we get a palindrome (24089544598042).

The spelling of 13045540044011 in words is "thirteen trillion, forty-five billion, five hundred forty million, forty-four thousand, eleven".