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130473544506443 is a prime number
BaseRepresentation
bin11101101010101000111101…
…010001011101110001001011
3122002222011000122112200101122
4131222220331101131301023
5114100134304343201233
61141254415140105455
736324255030456245
oct3552507521356113
9562864018480348
10130473544506443
1138633579487866
121277279209528b
1357a57aa78b258
142430d4b9dd095
151013db2851d98
hex76aa3d45dc4b

130473544506443 has 2 divisors, whose sum is σ = 130473544506444. Its totient is φ = 130473544506442.

The previous prime is 130473544506413. The next prime is 130473544506457. The reversal of 130473544506443 is 344605445374031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130473544506443 - 26 = 130473544506379 is a prime.

It is not a weakly prime, because it can be changed into another prime (130473544506413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65236772253221 + 65236772253222.

It is an arithmetic number, because the mean of its divisors is an integer number (65236772253222).

Almost surely, 2130473544506443 is an apocalyptic number.

130473544506443 is a deficient number, since it is larger than the sum of its proper divisors (1).

130473544506443 is an equidigital number, since it uses as much as digits as its factorization.

130473544506443 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 29030400, while the sum is 53.

The spelling of 130473544506443 in words is "one hundred thirty trillion, four hundred seventy-three billion, five hundred forty-four million, five hundred six thousand, four hundred forty-three".