Base | Representation |
---|---|
bin | 11101101010101000111101… |
… | …010001011101110001001011 |
3 | 122002222011000122112200101122 |
4 | 131222220331101131301023 |
5 | 114100134304343201233 |
6 | 1141254415140105455 |
7 | 36324255030456245 |
oct | 3552507521356113 |
9 | 562864018480348 |
10 | 130473544506443 |
11 | 38633579487866 |
12 | 1277279209528b |
13 | 57a57aa78b258 |
14 | 2430d4b9dd095 |
15 | 1013db2851d98 |
hex | 76aa3d45dc4b |
130473544506443 has 2 divisors, whose sum is σ = 130473544506444. Its totient is φ = 130473544506442.
The previous prime is 130473544506413. The next prime is 130473544506457. The reversal of 130473544506443 is 344605445374031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130473544506443 - 26 = 130473544506379 is a prime.
It is not a weakly prime, because it can be changed into another prime (130473544506413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65236772253221 + 65236772253222.
It is an arithmetic number, because the mean of its divisors is an integer number (65236772253222).
Almost surely, 2130473544506443 is an apocalyptic number.
130473544506443 is a deficient number, since it is larger than the sum of its proper divisors (1).
130473544506443 is an equidigital number, since it uses as much as digits as its factorization.
130473544506443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 29030400, while the sum is 53.
The spelling of 130473544506443 in words is "one hundred thirty trillion, four hundred seventy-three billion, five hundred forty-four million, five hundred six thousand, four hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •