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130481232593 is a prime number
BaseRepresentation
bin111100110000101001…
…0011001101011010001
3110110210110110101122012
41321201102121223101
54114211143420333
6135535305352305
712266306114555
oct1714122315321
9413713411565
10130481232593
1150378288318
1221355a98695
13c3c57b854a
14645b377865
1535da220e48
hex1e61499ad1

130481232593 has 2 divisors, whose sum is σ = 130481232594. Its totient is φ = 130481232592.

The previous prime is 130481232559. The next prime is 130481232617. The reversal of 130481232593 is 395232184031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 66870339649 + 63610892944 = 258593^2 + 252212^2 .

It is a cyclic number.

It is not a de Polignac number, because 130481232593 - 216 = 130481167057 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130481232593.

It is not a weakly prime, because it can be changed into another prime (130481231593) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65240616296 + 65240616297.

It is an arithmetic number, because the mean of its divisors is an integer number (65240616297).

Almost surely, 2130481232593 is an apocalyptic number.

It is an amenable number.

130481232593 is a deficient number, since it is larger than the sum of its proper divisors (1).

130481232593 is an equidigital number, since it uses as much as digits as its factorization.

130481232593 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 155520, while the sum is 41.

The spelling of 130481232593 in words is "one hundred thirty billion, four hundred eighty-one million, two hundred thirty-two thousand, five hundred ninety-three".