Base | Representation |
---|---|
bin | 10010111111011011001… |
… | …110110111111100000101 |
3 | 11121202120101211121122122 |
4 | 102333123032313330011 |
5 | 132340222104401013 |
6 | 2435311055135325 |
7 | 163200302112314 |
oct | 22773316677405 |
9 | 4552511747578 |
10 | 1305053200133 |
11 | 463519566251 |
12 | 190b17814545 |
13 | 960b1c91ba7 |
14 | 4724473827b |
15 | 23e32889a08 |
hex | 12fdb3b7f05 |
1305053200133 has 2 divisors, whose sum is σ = 1305053200134. Its totient is φ = 1305053200132.
The previous prime is 1305053200097. The next prime is 1305053200207. The reversal of 1305053200133 is 3310023505031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1298726906689 + 6326293444 = 1139617^2 + 79538^2 .
It is a cyclic number.
It is not a de Polignac number, because 1305053200133 - 224 = 1305036422917 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1305053203133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652526600066 + 652526600067.
It is an arithmetic number, because the mean of its divisors is an integer number (652526600067).
Almost surely, 21305053200133 is an apocalyptic number.
It is an amenable number.
1305053200133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1305053200133 is an equidigital number, since it uses as much as digits as its factorization.
1305053200133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4050, while the sum is 26.
Adding to 1305053200133 its reverse (3310023505031), we get a palindrome (4615076705164).
The spelling of 1305053200133 in words is "one trillion, three hundred five billion, fifty-three million, two hundred thousand, one hundred thirty-three".
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