Base | Representation |
---|---|
bin | 10010111111100000000… |
… | …110111110011001010111 |
3 | 11121202210002210021020211 |
4 | 102333200012332121113 |
5 | 132340404030444021 |
6 | 2435323140510251 |
7 | 163202314406155 |
oct | 22774006763127 |
9 | 4552702707224 |
10 | 1305135015511 |
11 | 463560767368 |
12 | 190b3b0ab387 |
13 | 960c5c09662 |
14 | 472515543d5 |
15 | 23e39b4b3e1 |
hex | 12fe01be657 |
1305135015511 has 2 divisors, whose sum is σ = 1305135015512. Its totient is φ = 1305135015510.
The previous prime is 1305135015413. The next prime is 1305135015559. The reversal of 1305135015511 is 1155105315031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1305135015511 is a prime.
It is a super-2 number, since 2×13051350155112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1305135015581) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652567507755 + 652567507756.
It is an arithmetic number, because the mean of its divisors is an integer number (652567507756).
Almost surely, 21305135015511 is an apocalyptic number.
1305135015511 is a deficient number, since it is larger than the sum of its proper divisors (1).
1305135015511 is an equidigital number, since it uses as much as digits as its factorization.
1305135015511 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5625, while the sum is 31.
The spelling of 1305135015511 in words is "one trillion, three hundred five billion, one hundred thirty-five million, fifteen thousand, five hundred eleven".
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