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13052113 is a prime number
BaseRepresentation
bin110001110010…
…100011010001
3220120010010121
4301302203101
511320131423
61143430241
7215640544
oct61624321
926503117
1013052113
117405278
124455381
13291cb59
141a3a85b
15122c45d
hexc728d1

13052113 has 2 divisors, whose sum is σ = 13052114. Its totient is φ = 13052112.

The previous prime is 13052111. The next prime is 13052119. The reversal of 13052113 is 31125031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12730624 + 321489 = 3568^2 + 567^2 .

It is a cyclic number.

It is not a de Polignac number, because 13052113 - 21 = 13052111 is a prime.

Together with 13052111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13052111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6526056 + 6526057.

It is an arithmetic number, because the mean of its divisors is an integer number (6526057).

Almost surely, 213052113 is an apocalyptic number.

It is an amenable number.

13052113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13052113 is an equidigital number, since it uses as much as digits as its factorization.

13052113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90, while the sum is 16.

The square root of 13052113 is about 3612.7708202985. The cubic root of 13052113 is about 235.4472424466.

Adding to 13052113 its reverse (31125031), we get a palindrome (44177144).

The spelling of 13052113 in words is "thirteen million, fifty-two thousand, one hundred thirteen".