Base | Representation |
---|---|
bin | 111100110001110101… |
… | …0101011001110000101 |
3 | 110110220020120102111022 |
4 | 1321203222223032011 |
5 | 4114301403302331 |
6 | 135543253120525 |
7 | 12300302321051 |
oct | 1714352531605 |
9 | 413806512438 |
10 | 130521150341 |
11 | 5039887209a |
12 | 21367329145 |
13 | c400b5380a |
14 | 64627a8c61 |
15 | 35dd9a867b |
hex | 1e63aab385 |
130521150341 has 2 divisors, whose sum is σ = 130521150342. Its totient is φ = 130521150340.
The previous prime is 130521150269. The next prime is 130521150349. The reversal of 130521150341 is 143051125031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 74862432100 + 55658718241 = 273610^2 + 235921^2 .
It is a cyclic number.
It is not a de Polignac number, because 130521150341 - 214 = 130521133957 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130521150341.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130521150349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65260575170 + 65260575171.
It is an arithmetic number, because the mean of its divisors is an integer number (65260575171).
Almost surely, 2130521150341 is an apocalyptic number.
It is an amenable number.
130521150341 is a deficient number, since it is larger than the sum of its proper divisors (1).
130521150341 is an equidigital number, since it uses as much as digits as its factorization.
130521150341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 26.
Adding to 130521150341 its reverse (143051125031), we get a palindrome (273572275372).
The spelling of 130521150341 in words is "one hundred thirty billion, five hundred twenty-one million, one hundred fifty thousand, three hundred forty-one".
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