Base | Representation |
---|---|
bin | 10010111111101010110… |
… | …011010110010101000010 |
3 | 11121210020121100221222210 |
4 | 102333222303112111002 |
5 | 132341240442420114 |
6 | 2435353030042550 |
7 | 163206623334342 |
oct | 22775263262502 |
9 | 4553217327883 |
10 | 1305314420034 |
11 | 463642a62669 |
12 | 190b8b1a9456 |
13 | 96124132491 |
14 | 4726b2d4d22 |
15 | 23e4a788259 |
hex | 12feacd6542 |
1305314420034 has 128 divisors (see below), whose sum is σ = 2731674274560. Its totient is φ = 415516774400.
The previous prime is 1305314420021. The next prime is 1305314420051. The reversal of 1305314420034 is 4300244135031.
It is a super-2 number, since 2×13053144200342 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1305314419983 and 1305314420010.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 763787572 + ... + 763789280.
It is an arithmetic number, because the mean of its divisors is an integer number (21341205270).
Almost surely, 21305314420034 is an apocalyptic number.
1305314420034 is an abundant number, since it is smaller than the sum of its proper divisors (1426359854526).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1305314420034 is a wasteful number, since it uses less digits than its factorization.
1305314420034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2196.
The product of its (nonzero) digits is 17280, while the sum is 30.
Adding to 1305314420034 its reverse (4300244135031), we get a palindrome (5605558555065).
The spelling of 1305314420034 in words is "one trillion, three hundred five billion, three hundred fourteen million, four hundred twenty thousand, thirty-four".
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