Base | Representation |
---|---|
bin | 1011110111110011111110… |
… | …0000010000010001111100 |
3 | 1201012220021211200102021112 |
4 | 2331330333200100101330 |
5 | 3202332002041014234 |
6 | 43432403134221152 |
7 | 2515040116025303 |
oct | 275747740202174 |
9 | 51186254612245 |
10 | 13053471032444 |
11 | 4182a451048a7 |
12 | 1569a250547b8 |
13 | 738c2489169b |
14 | 331b1173343a |
15 | 17983db15ace |
hex | bdf3f81047c |
13053471032444 has 24 divisors (see below), whose sum is σ = 23581677361536. Its totient is φ = 6315870600000.
The previous prime is 13053471032443. The next prime is 13053471032447. The reversal of 13053471032444 is 44423017435031.
It is a super-2 number, since 2×130534710324442 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13053471032443) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 280967 + ... + 5117214.
It is an arithmetic number, because the mean of its divisors is an integer number (982569890064).
Almost surely, 213053471032444 is an apocalyptic number.
It is an amenable number.
13053471032444 is a deficient number, since it is larger than the sum of its proper divisors (10528206329092).
13053471032444 is a wasteful number, since it uses less digits than its factorization.
13053471032444 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5417717 (or 5417715 counting only the distinct ones).
The product of its (nonzero) digits is 483840, while the sum is 41.
Adding to 13053471032444 its reverse (44423017435031), we get a palindrome (57476488467475).
The spelling of 13053471032444 in words is "thirteen trillion, fifty-three billion, four hundred seventy-one million, thirty-two thousand, four hundred forty-four".
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