Base | Representation |
---|---|
bin | 111100110010010100… |
… | …0001001001000011001 |
3 | 110110221100220001210012 |
4 | 1321210220021020121 |
5 | 4114320014414031 |
6 | 135545030331305 |
7 | 12300556301441 |
oct | 1714450111031 |
9 | 413840801705 |
10 | 130537263641 |
11 | 503a6978274 |
12 | 213707b9b35 |
13 | c4042a5b05 |
14 | 64649a1121 |
15 | 35e00dcb2b |
hex | 1e64a09219 |
130537263641 has 2 divisors, whose sum is σ = 130537263642. Its totient is φ = 130537263640.
The previous prime is 130537263611. The next prime is 130537263671. The reversal of 130537263641 is 146362735031.
It is a balanced prime because it is at equal distance from previous prime (130537263611) and next prime (130537263671).
It can be written as a sum of positive squares in only one way, i.e., 89059868041 + 41477395600 = 298429^2 + 203660^2 .
It is a cyclic number.
It is not a de Polignac number, because 130537263641 - 214 = 130537247257 is a prime.
It is not a weakly prime, because it can be changed into another prime (130537263611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65268631820 + 65268631821.
It is an arithmetic number, because the mean of its divisors is an integer number (65268631821).
Almost surely, 2130537263641 is an apocalyptic number.
It is an amenable number.
130537263641 is a deficient number, since it is larger than the sum of its proper divisors (1).
130537263641 is an equidigital number, since it uses as much as digits as its factorization.
130537263641 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 272160, while the sum is 41.
Adding to 130537263641 its reverse (146362735031), we get a palindrome (276899998672).
The spelling of 130537263641 in words is "one hundred thirty billion, five hundred thirty-seven million, two hundred sixty-three thousand, six hundred forty-one".
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