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13053930059969 is a prime number
BaseRepresentation
bin1011110111110101101011…
…0111010011100011000001
31201012221110211102102122222
42331331122313103203001
53202333422043404334
643432520452540425
72515054361504051
oct275753267234301
951187424372588
1013053930059969
114183160226a97
121569b32921715
13738c989cc3c6
14331b566a1561
15179869088d2e
hexbdf5add38c1

13053930059969 has 2 divisors, whose sum is σ = 13053930059970. Its totient is φ = 13053930059968.

The previous prime is 13053930059959. The next prime is 13053930059971. The reversal of 13053930059969 is 96995003935031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8688275017744 + 4365655042225 = 2947588^2 + 2089415^2 .

It is a cyclic number.

It is not a de Polignac number, because 13053930059969 - 28 = 13053930059713 is a prime.

It is a super-2 number, since 2×130539300599692 (a number of 27 digits) contains 22 as substring.

Together with 13053930059971, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13053930059939) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6526965029984 + 6526965029985.

It is an arithmetic number, because the mean of its divisors is an integer number (6526965029985).

Almost surely, 213053930059969 is an apocalyptic number.

It is an amenable number.

13053930059969 is a deficient number, since it is larger than the sum of its proper divisors (1).

13053930059969 is an equidigital number, since it uses as much as digits as its factorization.

13053930059969 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26572050, while the sum is 62.

The spelling of 13053930059969 in words is "thirteen trillion, fifty-three billion, nine hundred thirty million, fifty-nine thousand, nine hundred sixty-nine".