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13054110024312 = 233573919244781
BaseRepresentation
bin1011110111110110010110…
…0101110100001001111000
31201012221221101001120100000
42331331211211310021320
53202334304131234222
643432550402113000
72515062005253330
oct275754545641170
951187841046300
1013054110024312
114183242874955
121569b8304b760
13738cc708cc96
14331b7254a0c0
15179879c869ac
hexbdf65974278

13054110024312 has 192 divisors, whose sum is σ = 41912944819200. Its totient is φ = 3728778779520.

The previous prime is 13054110024287. The next prime is 13054110024367. The reversal of 13054110024312 is 21342001145031.

13054110024312 is a `hidden beast` number, since 1 + 3 + 0 + 5 + 411 + 0 + 0 + 243 + 1 + 2 = 666.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 53207362 + ... + 53452142.

It is an arithmetic number, because the mean of its divisors is an integer number (218296587600).

Almost surely, 213054110024312 is an apocalyptic number.

13054110024312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13054110024312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20956472409600).

13054110024312 is an abundant number, since it is smaller than the sum of its proper divisors (28858834794888).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13054110024312 is a wasteful number, since it uses less digits than its factorization.

13054110024312 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 248728 (or 248712 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 27.

Adding to 13054110024312 its reverse (21342001145031), we get a palindrome (34396111169343).

The spelling of 13054110024312 in words is "thirteen trillion, fifty-four billion, one hundred ten million, twenty-four thousand, three hundred twelve".