Base | Representation |
---|---|
bin | 11101101011100111111100… |
… | …001010000100000111100011 |
3 | 122010012121120200201010102002 |
4 | 131223213330022010013203 |
5 | 114102241304402232232 |
6 | 1141345441501514215 |
7 | 36332200631600033 |
oct | 3553477412040743 |
9 | 563177520633362 |
10 | 130541171524067 |
11 | 3865a222140077 |
12 | 1278390627296b |
13 | 57abc973b9605 |
14 | 24343253c98c3 |
15 | 1015a1e976b62 |
hex | 76b9fc2841e3 |
130541171524067 has 2 divisors, whose sum is σ = 130541171524068. Its totient is φ = 130541171524066.
The previous prime is 130541171524037. The next prime is 130541171524079. The reversal of 130541171524067 is 760425171145031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130541171524067 - 232 = 130536876556771 is a prime.
It is not a weakly prime, because it can be changed into another prime (130541171524037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65270585762033 + 65270585762034.
It is an arithmetic number, because the mean of its divisors is an integer number (65270585762034).
Almost surely, 2130541171524067 is an apocalyptic number.
130541171524067 is a deficient number, since it is larger than the sum of its proper divisors (1).
130541171524067 is an equidigital number, since it uses as much as digits as its factorization.
130541171524067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 705600, while the sum is 47.
The spelling of 130541171524067 in words is "one hundred thirty trillion, five hundred forty-one billion, one hundred seventy-one million, five hundred twenty-four thousand, sixty-seven".
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