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130542017 is a prime number
BaseRepresentation
bin1111100011111…
…10100111000001
3100002122012222112
413301332213001
5231404321032
620541545105
73143405654
oct761764701
9302565875
10130542017
1167762171
1237875195
13210783c8
14134a189b
15b6d91b2
hex7c7e9c1

130542017 has 2 divisors, whose sum is σ = 130542018. Its totient is φ = 130542016.

The previous prime is 130542011. The next prime is 130542019. The reversal of 130542017 is 710245031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 122567041 + 7974976 = 11071^2 + 2824^2 .

It is an emirp because it is prime and its reverse (710245031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130542017 - 26 = 130541953 is a prime.

Together with 130542019, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 130541983 and 130542001.

It is not a weakly prime, because it can be changed into another prime (130542011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65271008 + 65271009.

It is an arithmetic number, because the mean of its divisors is an integer number (65271009).

Almost surely, 2130542017 is an apocalyptic number.

It is an amenable number.

130542017 is a deficient number, since it is larger than the sum of its proper divisors (1).

130542017 is an equidigital number, since it uses as much as digits as its factorization.

130542017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 840, while the sum is 23.

The square root of 130542017 is about 11425.4985449214. The cubic root of 130542017 is about 507.2827636824.

Adding to 130542017 its reverse (710245031), we get a palindrome (840787048).

The spelling of 130542017 in words is "one hundred thirty million, five hundred forty-two thousand, seventeen".