Base | Representation |
---|---|
bin | 10010111111110001010… |
… | …010000110000011001101 |
3 | 11121210112011221200000122 |
4 | 102333301102012003031 |
5 | 132342001311034432 |
6 | 2435411512234325 |
7 | 163212413430302 |
oct | 22776122060315 |
9 | 4553464850018 |
10 | 1305423143117 |
11 | 463699371955 |
12 | 190bbb69b9a5 |
13 | 9614080b572 |
14 | 4727b9170a9 |
15 | 23e550b2612 |
hex | 12ff14860cd |
1305423143117 has 2 divisors, whose sum is σ = 1305423143118. Its totient is φ = 1305423143116.
The previous prime is 1305423143113. The next prime is 1305423143173. The reversal of 1305423143117 is 7113413245031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1291027702756 + 14395440361 = 1136234^2 + 119981^2 .
It is an emirp because it is prime and its reverse (7113413245031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1305423143117 - 22 = 1305423143113 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1305423143113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652711571558 + 652711571559.
It is an arithmetic number, because the mean of its divisors is an integer number (652711571559).
Almost surely, 21305423143117 is an apocalyptic number.
It is an amenable number.
1305423143117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1305423143117 is an equidigital number, since it uses as much as digits as its factorization.
1305423143117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30240, while the sum is 35.
Adding to 1305423143117 its reverse (7113413245031), we get a palindrome (8418836388148).
The spelling of 1305423143117 in words is "one trillion, three hundred five billion, four hundred twenty-three million, one hundred forty-three thousand, one hundred seventeen".
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