Base | Representation |
---|---|
bin | 10010111111110001010… |
… | …101110010011100011111 |
3 | 11121210112020202212020122 |
4 | 102333301111302130133 |
5 | 132342002033031031 |
6 | 2435411545105155 |
7 | 163212424602251 |
oct | 22776125623437 |
9 | 4553466685218 |
10 | 1305424111391 |
11 | 463699973384 |
12 | 190bbba881bb |
13 | 96140a8a1ca |
14 | 4727bac9cd1 |
15 | 23e5520447b |
hex | 12ff157271f |
1305424111391 has 2 divisors, whose sum is σ = 1305424111392. Its totient is φ = 1305424111390.
The previous prime is 1305424111361. The next prime is 1305424111447. The reversal of 1305424111391 is 1931114245031.
It is a weak prime.
It is an emirp because it is prime and its reverse (1931114245031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1305424111391 - 238 = 1030546204447 is a prime.
It is a super-2 number, since 2×13054241113912 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1305424111361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652712055695 + 652712055696.
It is an arithmetic number, because the mean of its divisors is an integer number (652712055696).
Almost surely, 21305424111391 is an apocalyptic number.
1305424111391 is a deficient number, since it is larger than the sum of its proper divisors (1).
1305424111391 is an equidigital number, since it uses as much as digits as its factorization.
1305424111391 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12960, while the sum is 35.
The spelling of 1305424111391 in words is "one trillion, three hundred five billion, four hundred twenty-four million, one hundred eleven thousand, three hundred ninety-one".
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