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1305424111433 = 13208874807643
BaseRepresentation
bin10010111111110001010…
…101110010011101001001
311121210112020202212022012
4102333301111302131021
5132342002033031213
62435411545105305
7163212424602341
oct22776125623511
94553466685265
101305424111433
11463699973412
12190bbba88235
1396140a8a230
144727bac9d21
1523e552044a8
hex12ff1572749

1305424111433 has 8 divisors (see below), whose sum is σ = 1405908950208. Its totient is φ = 1204948929744.

The previous prime is 1305424111391. The next prime is 1305424111447. The reversal of 1305424111433 is 3341114245031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1305424111433 - 238 = 1030546204489 is a prime.

It is a super-2 number, since 2×13054241114332 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1305424111433.

It is not an unprimeable number, because it can be changed into a prime (1305424111333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2132291 + ... + 2675352.

It is an arithmetic number, because the mean of its divisors is an integer number (175738618776).

Almost surely, 21305424111433 is an apocalyptic number.

1305424111433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1305424111433 is a deficient number, since it is larger than the sum of its proper divisors (100484838775).

1305424111433 is a wasteful number, since it uses less digits than its factorization.

1305424111433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4828543.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 1305424111433 its reverse (3341114245031), we get a palindrome (4646538356464).

The spelling of 1305424111433 in words is "one trillion, three hundred five billion, four hundred twenty-four million, one hundred eleven thousand, four hundred thirty-three".

Divisors: 1 13 20887 271531 4807643 62499359 100417239341 1305424111433