Base | Representation |
---|---|
bin | 10010111111110001010… |
… | …101110010011101001000 |
3 | 11121210112020202212022011 |
4 | 102333301111302131020 |
5 | 132342002033031212 |
6 | 2435411545105304 |
7 | 163212424602340 |
oct | 22776125623510 |
9 | 4553466685264 |
10 | 1305424111432 |
11 | 463699973411 |
12 | 190bbba88234 |
13 | 96140a8a22c |
14 | 4727bac9d20 |
15 | 23e552044a7 |
hex | 12ff1572748 |
1305424111432 has 16 divisors (see below), whose sum is σ = 2797337381760. Its totient is φ = 559467476304.
The previous prime is 1305424111391. The next prime is 1305424111447. The reversal of 1305424111432 is 2341114245031.
It is a happy number.
It is a super-2 number, since 2×13054241114322 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1305424111394 and 1305424111403.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11655572368 + ... + 11655572479.
It is an arithmetic number, because the mean of its divisors is an integer number (174833586360).
Almost surely, 21305424111432 is an apocalyptic number.
It is an amenable number.
1305424111432 is an abundant number, since it is smaller than the sum of its proper divisors (1491913270328).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1305424111432 is a wasteful number, since it uses less digits than its factorization.
1305424111432 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23311144860 (or 23311144856 counting only the distinct ones).
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 1305424111432 its reverse (2341114245031), we get a palindrome (3646538356463).
The spelling of 1305424111432 in words is "one trillion, three hundred five billion, four hundred twenty-four million, one hundred eleven thousand, four hundred thirty-two".
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