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1305424513381 is a prime number
BaseRepresentation
bin10010111111110001010…
…111010100100101100101
311121210112021112021200011
4102333301113110211211
5132342002133412011
62435412001450221
7163212431165242
oct22776127244545
94553467467604
101305424513381
1146369a1183aa
12191000040971
1396140b9b181
144727bb925c9
1523e55283621
hex12ff15d4965

1305424513381 has 2 divisors, whose sum is σ = 1305424513382. Its totient is φ = 1305424513380.

The previous prime is 1305424513373. The next prime is 1305424513451. The reversal of 1305424513381 is 1833154245031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 802188922500 + 503235590881 = 895650^2 + 709391^2 .

It is a cyclic number.

It is not a de Polignac number, because 1305424513381 - 23 = 1305424513373 is a prime.

It is a super-2 number, since 2×13054245133812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1305424513361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652712256690 + 652712256691.

It is an arithmetic number, because the mean of its divisors is an integer number (652712256691).

Almost surely, 21305424513381 is an apocalyptic number.

It is an amenable number.

1305424513381 is a deficient number, since it is larger than the sum of its proper divisors (1).

1305424513381 is an equidigital number, since it uses as much as digits as its factorization.

1305424513381 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 172800, while the sum is 40.

The spelling of 1305424513381 in words is "one trillion, three hundred five billion, four hundred twenty-four million, five hundred thirteen thousand, three hundred eighty-one".